Regex, Removing Recurring Characters But Keeping At Least One April 19, 2024 Post a Comment I'm using this html = html.replace(/([^0-9]).*?\1/ , ''); but it's not quite doing what I'm trying to do. I want to replace the doubles within a string, but still keep at least oSolution 1: THink you mean this,str.replace(/(.)\1+/g, '$1') Copyor str.replace(/([^0-9])\1+/g, '$1') CopyBaca JugaReading Multiple Xml Attributes With QmlMaking A Pipe With Regex On Angular2How To Use Just Asterisk Wildcard When Searching? Share You may like these postsBest Way To Parse A Javascript File In Php To Extract The Array Defined Inside ItJavascript Regex Matching Is Ignoring Literal DotHow To Put Variable In Regular Expression Match?How To Replace "\" With "\\" From A String Using Javascript? Post a Comment for "Regex, Removing Recurring Characters But Keeping At Least One"
Post a Comment for "Regex, Removing Recurring Characters But Keeping At Least One"