Destructuring An Object Without Specifying Its Properties

Is there an elegant solution to destructure an object without specifying all the object's properties? I wondered if it was possible to use the spread operator but it seems like tha

Solution 1:

This is what the with(){} construction allowed:

var obj = {a: 1};
with (obj) {
  console.log(a);
}

This construct is however severely discouraged and basically deprecated (it throws an error in strict mode), because it has some major drawbacks:

• Your code is hard to read, because it's impossible to tell apart 1) Variables from outer scopes 2) Local variables 3) Properties coming from the object.

• Your code can't be optimized, because the JavaScript engine can't tell where your variables are coming from.

• Your code is much harder to refactor, because if you introduce a property to your obj, it might shadow some existing local variable, exemple:

---

var obj = {};
var a = 1;
addSomeProperties(obj);
with (obj) {
  console.log(a); // the result here depends on whether or not "addSomeProperties" puts a property named "a" on "obj"
}

---

TL;DR version: you really don't want this, it makes your code brittle, hard to read&refactor. Just pick the pieces you want apart using the "normal" destructuring syntax.